CODEWITHSUNDEEP
pythonpytorch
yusuf
yusuf

Reputation: 3781

reshaping a tensor with padding in pytorch

How do I reshape a tensor with dimensions (30, 35, 49) to (30, 35, 512) by padding it?

Upvotes: 51

Views: 109811

Answers (6)

fanbyprinciple
fanbyprinciple

Reputation: 790

Just wanted to illustrate the answer given by @ghchoi. Because I had a little trouble following it.

I want to fit an image from standard mnist of size (N,1,28,28) into LeNet (proposed way back in 1998) due to kernel size restriction expects the input to be of the shape (N,1,32,32). So suppose we try to mitigate this problem by padding.

before padding

before padding a single image, it is of the size (1,28,28). Thus we have three dimensions.

before_padding

after padding

after padding , to create an image of size (1,32,32). Notice the pad=(2,2,2,2,0,0)

This is because I added two zeros to the x axis before and after the first (2,2) and two zeros after yaxis (2,2), leaving the channel column alone thus (0,0). value indicates that the padding would be 0.

after_padding

Thanks!

Upvotes: 2

Sankalp1999
Sankalp1999

Reputation: 31

The idea here is to use torch.cat to pad across that particular dimension with your desired tensor. The example should make it clearer.

In [1]: import torch

In [2]: a = torch.randn(30, 35, 49)

In [3]: b = torch.randn(30, 35, 512)

In [4]: padder = torch.zeros(30,35,512 - 49)

In [5]: padded_a = torch.cat([a,padder], dim = 2) # Choose your desired dim

In [6]: padded_a.shape
Out[6]: torch.Size([30, 35, 512])

In [7]: target = torch.randn(30,35,512)

In [8]: target = torch.cat([target,padded_a], dim = 2)

In [9]: target.shape
Out[9]: torch.Size([30, 35, 1024])

Upvotes: 2

Biplob Das
Biplob Das

Reputation: 3104

enter image description here

import torch.nn.functional as F
data = torch.ones(4, 4)
# pad(left, right, top, bottom)
new_data = F.pad(input=data, pad=(1, 1, 1, 1), mode='constant', value=0)
print(new_data)

Upvotes: 8

cookiemonster
cookiemonster

Reputation: 2134

A module that might be clearer and more suitable for this question is torch.nn.ConstantPad1d e.g. 

import torch
from torch import nn

x = torch.ones(30, 35, 49)
padded = nn.ConstantPad1d((0, 512 - 49), 0)(x)

Upvotes: 14

cleros
cleros

Reputation: 4343

While @nemo's solution works fine, there is a pytorch internal routine, torch.nn.functional.pad, that does the same - and which has a couple of properties that a torch.ones(*sizes)*pad_value solution does not (namely other forms of padding, like reflection padding or replicate padding ... it also checks some gradient-related properties):

import torch.nn.functional as F
source = torch.rand((5,10))
# now we expand to size (7, 11) by appending a row of 0s at pos 0 and pos 6, 
# and a column of 0s at pos 10
result = F.pad(input=source, pad=(0, 1, 1, 1), mode='constant', value=0)

The semantics of the arguments are:

  • input: the source tensor,
  • pad: a list of length 2 * len(source.shape) of the form (begin last axis, end last axis, begin 2nd to last axis, end 2nd to last axis, begin 3rd to last axis, etc.) that states how many dimensions should be added to the beginning and end of each axis,
  • mode: 'constant', 'reflect' or 'replicate'. Default: 'constant' for the different kinds of padding
  • value for constant padding.

Upvotes: 62

nemo
nemo

Reputation: 57739

The simplest solution is to allocate a tensor with your padding value and the target dimensions and assign the portion for which you have data:

target = torch.zeros(30, 35, 512)
source = torch.ones(30, 35, 49)
target[:, :, :49] = source

Note that there is no guarantee that padding your tensor with zeros and then multiplying it with another tensor makes sense in the end, that is up to you.

Upvotes: 45

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