CODEWITHSUNDEEP
phphtml
Lawrence Chong
Lawrence Chong

Reputation: 45

PHP display download link at email

This one is my code to display at email , my folder got 5 item , but it only display one link only , by right it should display 5 link

 $files = glob("../booking/file/".$id."/*.*");
        for ($i=0; $i<count($files); $i++)
        {
            $image = $files[$i];
            $supported_file = array('gif','jpg','jpeg','png', 'pdf');

            $d = $i + 1;
            $ext = strtolower(pathinfo($image, PATHINFO_EXTENSION));
            if (in_array($ext, $supported_file)) {
                $attch = '<a href="localhost/linxtravel/travelnew/travelnew/'.$image.'" target="_blank">('.$d.') Click here to download.</a><br/>';
                $checkattch = 1;
            } else {
                continue;
            }
        }

Upvotes: 1

Views: 70

Answers (2)

Syscall
Syscall

Reputation: 19780

You have to concatenate the string using .= :

$attch .= '<a href="localhost/linxtravel/travelnew/travelnew/'.$image.'" target="_blank">('.$d.') Click here to download.</a><br/>';

Without, you overrides the variable $attch and you gets only the last link.

Upvotes: 1

Vladimir
Vladimir

Reputation: 1391

In this place you always rewrite variable $attch each loop:

$attch = '<a href="localhost/linxtravel/travelnew/travelnew/'.$image.'" target="_blank">('.$d.') Click here to download.</a><br/>';

You need to append like this:

$attch. = '<a href="localhost/linxtravel/travelnew/travelnew/'.$image.'" target="_blank">('.$d.') Click here to download.</a><br/>';

And declarate variable before loop for:

$attch = '';

Upvotes: 1

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