CODEWITHSUNDEEP
pythonfunctionnonetype
ChameleonX
ChameleonX

Reputation: 87

Python 3 Not void function still returning None Type

I'm writing an initial fruitful function with a return value int. I then create a void function with a simple print statement in the body with no return value, therefore, None type. However when I create a third function that calls the fruitful function in the body, therefore the third function will return a value it's still a None type. I've read the stack previously questions here, here and here However, could not find a solution.

Here is my code:

def return_something():
    return 3

def return_void_test():
    print('VOID')

def return_void_filled():
    #This has inside a RETURN VALUE
    print(return_something())
    return_something()


 print(return_something()) 
 print(return_something)
 j = return_something()
 print(type(j),'\n')

 print(return_void_test())
 print(return_void_test)
 k = return_void_test()
 print(type(k),'\n')

 print(return_void_filled())
 print(return_void_filled)
 g = return_void_filled()
 print(type(g))

Here is the result:

3
<function return_something at 0x000001CEEF392E18>
<class 'int'> 

VOID
None
<function return_void_test at 0x000001CEF10247B8>
VOID
<class 'NoneType'> 

3
None
<function return_void_filled at 0x000001CEF133B6A8>
3
<class 'NoneType'>

Process finished with exit code 0

What am I doing wrong? Why the third function still shows as a None Type when it should be int(as Returns a value int 3)? Thanks

Upvotes: 0

Views: 437

Answers (1)

Wright
Wright

Reputation: 3424

You aren't returning anything in your third function. You're only calling a function that does return something. Simply add a return

def return_void_filled():
    #This has inside a RETURN VALUE
    print(return_something())
    return return_something()

Upvotes: 2

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