CODEWITHSUNDEEP
phplaravelsymfony
Hanie Asemi
Hanie Asemi

Reputation: 1500

Symfony\Component\HttpKernel\Exception\HttpException Error in Laravel 5.4

I Want Register user with modal And Rapid Authentication,I'm Using Ajax for sent data. My Code is here:

 <div class="modal fade" tabindex="-1" role="dialog" id="mySignup">
    <div class="modal-dialog" role="document">
        <div class="login-wrap">
            <div class="form text-center">
                <input type="text" name="name" id="name"/>
                <input type="email"  name="email" id="email"/>
                <input type="password" name="pw" id="password"/>
                <button id="SignUp">Signup</button>
            </div>
        </div>
        {{csrf_field()}}
    </div>
</div>
<script>
$(document).ready(function () {
    $('#SignUp').click(function (event) {
        var name = $('#name').val();
        var email = $('#email').val();
        var password =$('#password').val();
        $.post('/register',{
            'name' : name,
            'email' :email,
            'password':password,
            'token':$('input[name=_token]').val()
        });
    });
});
</script>

And In Web.php I'm Using this code:

Route::post('/register',[
'as'=> '',
'uses' => 'Auth\RegisterController@Register'
 ]);

But When I Want SignUp I give this Error message with 419 status code {message: "", exception: "Symfony\Component\HttpKernel\Exception\HttpException",…} How I Can fix this problem?

Upvotes: 0

Views: 1512

Answers (2)

Niklesh Raut
Niklesh Raut

Reputation: 34914

change token to _token as laravel checks CSRF token in _token

'_token':$('input[name=_token]').val()

Upvotes: 1

bipin patel
bipin patel

Reputation: 2111

You need to pass token in header

<meta name="csrf-token" content="{{ csrf_token() }}">

Add header on ajax call 

headers: {
    'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
}

Upvotes: 0

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