Reputation: 9
I am using openimageIO to read and display an image from a JPG file, and I now need to store the RGB values in arrays so that I can manipulate and re-display them later.
I want to do something like this:
for (int i=0; i<picturesize;i++)
{
Rarray[i]=pixelredvalue;
Garray[i]=pixelgreenvalue;
Barray[i]=pixelbluevalue;
}
This is an openimageIO source that I found online: https://people.cs.clemson.edu/~dhouse/courses/404/papers/openimageio.pdf
"Section 3.2: Advanced Image Output" (pg 35) is the closest to what I'm doing, but I don't understand how I can use the channels to write pixel data to arrays. I also don't fully understand the difference between "writing" and "storing in an array". This is the piece of code in the reference that I am talking about:
int channels = 4;
ImageSpec spec (width, length, channels, TypeDesc::UINT8);
spec.channelnames.clear ();
spec.channelnames.push_back ("R");
spec.channelnames.push_back ("G");
spec.channelnames.push_back ("B");
spec.channelnames.push_back ("A");
I managed to read the image and display it using the code in the reference, but now I need to store all the pixel values in my array.
Here is another useful piece of code from the link, but again, I can't understand how to retrieve the individual RGB values and place them into an array:
#include <OpenImageIO/imageio.h>
OIIO_NAMESPACE_USING
...
const char *filename = "foo.jpg";
const int xres = 640, yres = 480;
const int channels = 3; // RGB
unsigned char pixels[xres*yres*channels];
ImageOutput *out = ImageOutput::create (filename);
if (! out)
return;
ImageSpec spec (xres, yres, channels, TypeDesc::UINT8);
out->open (filename, spec);
out->write_image (TypeDesc::UINT8, pixels);
out->close ();
ImageOutput::destroy (out);
But this is about writing to a file, and still does not solve my problem. This is on page 35.
Upvotes: 1
Views: 1002
Reputation: 211249
Let's assume, that your code which reads an image, looks like this (snippet from OpenImageIO 1.7 Programmer Documentation, Chapter 4.1 Image Input Made Simple, page 55):
ImageInput *in = ImageInput::open (filename);
const ImageSpec &spec = in->spec();
int xres = spec.width;
int yres = spec.height;
int channels = spec.nchannels;
std::vector<unsigned char> pixels (xres*yres*channels);
in->read_image (TypeDesc::UINT8, &pixels[0]);
in->close();
ImageInput::destroy (in);
Now all the bytes of the image are contained in std::vector<unsigned char> pixels
.
If you want to access the RGB valuse of the pixel at positon x
, y
, the you can do it like this:
int pixel_addr = (y * yres + x) * channels;
unsigned char red = pixels[pixel_addr];
unsigned char green = pixels[pixel_addr + 1];
unsigned char blue = pixels[pixel_addr + 2];
Since all the pixels are stored in pixels
, there is no reason to store them in separate arrays for the 3 color channels.
But if you want to store the red, green and blue values in separated arrays, then you can do it like this:
std::vector<unsigned char> Rarray(x_res*yres);
std::vector<unsigned char> Garray(x_res*yres);
std::vector<unsigned char> Barray(x_res*yres);
for (int i=0; i<x_res*yres; i++)
{
Rarray[i] = pixels[i*channels];
Garray[i] = pixels[i*channels + 1];
Barray[i] = pixels[i*channels + 2];
}
Of course the pixels have to be tightly packed to pixels
(line alignment of 1).
Upvotes: 1