CODEWITHSUNDEEP
swift
Abhinav Jha
Abhinav Jha

Reputation: 345

Want to print the data in new line

Edit 1 - I am getting the data from TextField and i have to display it in TextView. I cant post my code here, Hence this example

The below code give the output as abhisudeeptest where i want the output as required output

var x = "abhi"
var y = "sudeep"
var z = "test"
var a = ""
var arr = [String]()
arr.append(x)
arr.append(y)
arr.append(z)
for i in arr {
    a = a + i
}
print(a)

output - 

abhisudeeptest

required output

abhi
sudeep
test

Upvotes: 0

Views: 79

Answers (4)

Deepti Raghav
Deepti Raghav

Reputation: 902

try this-

 let x = "abhi"
    let y = "sudeep"
    let z = "test"
    var a = ""
    var b = ""
    var arr = [String]()
    arr.append(x)
    arr.append(y)
    arr.append(z)
    for i in 0..<arr.count
    {
        if  i == 0
        {
            a = a +  arr[i]
        }
        else
        {
            a = a + "\n" + arr[i]
        }
    }
    print (a)

or

 b = arr.joined(separator: "\n")
    print(b)

Upvotes: 0

Catherine
Catherine

Reputation: 682

Add a new line character:

var x = "abhi"
var y = "sudeep"
var z = "test"
var a = ""
var arr = [String]()
arr.append("\(x) \n")
arr.append("\(y) \n")
arr.append("\(z) \n")
for i in arr {
    a = a + i
}
print(a)

Upvotes: 0

Adrian Bobrowski
Adrian Bobrowski

Reputation: 2794

You can use joined(separator: )

let a = ["abhi", "sudeep", "test"].joined(separator: "\n")

print(a)

Upvotes: 3

rmaddy
rmaddy

Reputation: 318824

Add a newline:

a = a + i + "\n"

Upvotes: 1

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