Reputation: 113
I needed to anonymize IPv4 and IPv6 addresses so I coded this crude solution:
if (strlen($_SERVER['REMOTE_ADDR']) <= 15) { // Sorry: 15 NOT 12
echo htmlentities(substr_replace($_SERVER['REMOTE_ADDR'], 'XXX', -3), ENT_QUOTES);
} else {
echo htmlentities(substr_replace($_SERVER['REMOTE_ADDR'], 'XXXX:XXXX', -9), ENT_QUOTES);
}
It works fine with full length IPv4 and IPv6 addresses like
207.142.131.005
2001:0db8:0000:08d3:0000:8a2e:0070:7344
but not with abbreviated addresses like
207.142.131.5
2001:0db8::8d3::8a2e:7:7344
I wonder if there is an elegant solution with preg_replace and some regular expression magic?
Upvotes: 3
Views: 3034
Reputation: 48041
No conditional is necessary. You can write two patterns and two replacements for a single preg_replace()
call to process.
Target the optional numbers after the last literal dot in the string for replacement. Then target the alphanumeric colon-delimited substrings at the end of the string.
Code: (Demo)
$tests = [
"207.142.131.005",
"2001:0db8:0000:08d3:0000:8a2e:0070:7344",
"2001:0db8:0000:08d3:0000:8a2e:0070:734a",
"207.142.131.5",
"2001:0db8::8d3::8a2e:7:7344",
"::1",
"127.0.0.1"
];
$tests = preg_replace(
['/\.\d*$/', '/[\da-f]*:[\da-f]*$/'],
['.XXX', 'XXXX:XXXX'],
$tests
);
var_export($tests);
Output:
array (
0 => '207.142.131.XXX',
1 => '2001:0db8:0000:08d3:0000:8a2e:XXXX:XXXX',
2 => '2001:0db8:0000:08d3:0000:8a2e:XXXX:XXXX',
3 => '207.142.131.XXX',
4 => '2001:0db8::8d3::8a2e:XXXX:XXXX',
5 => ':XXXX:XXXX',
6 => '127.0.0.XXX',
)
Pattern Explanations:
IPv4:
/ #Pattern delimiter
\. #Match dot literally
\d* #Match zero or more digits
$ #Match the end of the string
/ #Pattern delimiter
IPv6
/ #Pattern delimiter
[\da-f]* #Match zero or more (digits or a b c d e f)
: #Match colon
[\da-f]* #Match zero or more (digits or a b c d e f)
$ #Match the end of the string
/ #Pattern delimiter
Upvotes: 10
Reputation: 3405
Regex: [0-9]+$
and [0-9]*:[0-9]+$
or \d+$
and \d*:\d+$
Details:
$
Asserts position at the end of a line[]
Match a single character present in the list+
Matches between one and unlimited times*
Matches between zero and unlimited timesPHP code:
function mask($ip)
{
if (strpos($ip, ".") == true) {
print_r(preg_replace('~[0-9]+$~', 'XXX', $ip) . "\n");
} else {
print_r(preg_replace('~[0-9]*:[0-9]+$~', 'XXXX:XXXX', $ip) . "\n");
}
}
Output:
207.142.131.XXX
207.142.131.XXX
2001:0db8:0000:08d3:0000:8a2e:XXXX:XXXX
2001:0db8::8d3::8a2e:XXXX:XXXX
:XXXX:XXXX
Upvotes: 1
Reputation: 23347
You can try:
$string = $_SERVER['REMOTE_ADDR'];
if (strlen($string) <= 12) {
echo htmlentities(preg_replace('/(\d+\.\d+.\d+.)(\d+)/', "$1XXX", $string), ENT_QUOTES);
} else {
echo htmlentities(preg_replace('/((?:[0-9a-f]+:){6})(\w+:\w+)/', "$1XXXX:XXXX", $string), ENT_QUOTES);
}
Upvotes: 0
Reputation: 9957
Without using regular expressions, you can explode by .
or :
accordingly and replace the last two pieces:
<?php
function anonIp($ip)
{
if (strpos($ip, ".") !== false) { // detect IP type by dots instead of length
$pieces = explode(".", $ip);
$nPieces = count($pieces);
$pieces[$nPieces - 1] = $pieces[$nPieces - 2] = "XXX";
return implode(".", $pieces);
} else {
$pieces = explode(":", $ip);
$nPieces = count($pieces);
$pieces[$nPieces - 1] = $pieces[$nPieces - 2] = "XXXX";
return implode(":", $pieces);
}
}
var_dump(anonIp("207.142.131.005")); // 207.142.XXX.XXX
var_dump(anonIp("2001:0db8:0000:08d3:0000:8a2e:0070:7344")); // 2001:0db8:0000:08d3:0000:8a2e:XXXX:XXXX
var_dump(anonIp("207.142.131.5")); // 207.142.XXX.XXX
var_dump(anonIp("2001:0db8::8d3::8a2e:7:7344")); // 2001:0db8::8d3::8a2e:XXXX:XXXX
var_dump(anonIp("::1")); // :XXXX:XXXX
var_dump(anonIp("127.0.0.1")); // 127.0.XXX.XXX
Though I'm sure there's some obscure (or not so much) case where this will break, so be sure to give it a thorough test first.
Upvotes: 1