CODEWITHSUNDEEP
javascript
Rambabu Bommisetti
Rambabu Bommisetti

Reputation: 137

How to compare two array objects and remove matched objects from one array object

My Code Scenario is:

var Employees= [{name:"Ram",htno:1245},{name:"mohan",htno:1246},
{name:"madhu",htno:1247},{name:"ranga",htno:1248}]

var seletedEmployees= [{name:"mohan"},{name:"ranga"}];

var employeesdataAfterremoveSelected = [?];

Upvotes: 0

Views: 65

Answers (6)

Rambabu Bommisetti
Rambabu Bommisetti

Reputation: 137

var Employees= [{name:"Ram",htno:1245},{name:"mohan",htno:1246}, {name:"madhu",htno:1247},{name:"ranga",htno:1248}]

var seletedEmployees= [{name:"mohan"},{name:"ranga"}];

var employeesdataAfterremoveSelected = Employees.filter(function(val,index) { console.log(val.name) return !(seletedEmployees.map(function(e) { return e.name; }).indexOf(val.name)); });

Upvotes: 0

Tomasz Bubała
Tomasz Bubała

Reputation: 2153

You can store selected employees names in an array and then filter Employees array and check if employee's name is in this array:

var employees= [{name:"Ram",htno:1245},{name:"mohan",htno:1246},{name:"madhu",htno:1247},{name:"ranga",htno:1248}]
var selectedEmployees= ["mohan","ranga"];
var result = employees.filter(emp => selectedEmployees.includes(emp.name));
console.log(result);

To programatically get array of strings instead array of objects, you can use map:

var seletedEmployees= [{name:"mohan"},{name:"ranga"}].map(emp => emp.name);

Upvotes: 1

zb22
zb22

Reputation: 3231

You can try this:

var Employees = [{name:"Ram",htno:1245},{name:"mohan",htno:1246},
    {name:"madhu",htno:1247},{name:"ranga",htno:1248}] 

var seletedEmployees = [{name:"mohan"},{name:"ranga"}];

var employeesdataAfterremoveSelected = Employees.filter(name => {
  return (name.name !== seletedEmployees[0].name && name.name !== seletedEmployees[1].name)
}) 

console.log(employeesdataAfterremoveSelected)

Upvotes: 1

digital-pollution
digital-pollution

Reputation: 1074

You can use the filter method, something like below (not tested)

var Employees = [{name:"Ram",htno:1245}, {name:"mohan",htno:1246}]

var SelectedEmployess = [{name:"Ram",htno:1245}]

// filter the items from the invalid list, out of the complete list
    var employeesdataAfterremoveSelected = Employees.filter((item.name) => {
    return !SelectedEmployess.has(item.name);
})

// get a Set of the distinct, valid items
var validItems = new Set(employeesdataAfterremoveSelected);

Upvotes: 1

user4676340
user4676340

Reputation:

Here is a one liner, decomposed to explain :

// Start by filtering the first array on a condition.
employeesdataAfterremoveSelected = Employees.filter(
  // Map the array of selected employees to only return the name
  e => seletedEmployees.map(_e => _e.name)
    // use the includes function to check if the name is in the array
    .includes(e.name)
);

In one line : 

employeesdataAfterremoveSelected = Employees.filter(e => seletedEmployees.map(_e => _e.name).includes(e.name));

Upvotes: 1

Akbar Badhusha
Akbar Badhusha

Reputation: 2627

From the code you have given above i think this might work

$.each(student, function(key, value){
   if(matchedvalues.indexOf(value.name) < 0)
     {
       employeesdataAfterremoveSelected.push(value.name);
     }
})

Upvotes: 1

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