CODEWITHSUNDEEP
phplaraveldatephp-carbon
Unai Susperregi
Unai Susperregi

Reputation: 414

Laravel Carbon diff not show 0 years

I use diff() function between 2 dates using Carbon

$fecha1 = \Carbon\Carbon::parse('2017-12-05');
$fecha2 = \Carbon\Carbon::parse('2018-02-09');
$resta = $fecha2->diff($fecha1)->format('%y years, %m months and %d days');

Result

0 years, 2 months and 4 days

I would like this result

2 months and 4 days

Because years is 0 Any solution?

Upvotes: 1

Views: 1672

Answers (3)

Mihai Matei
Mihai Matei

Reputation: 24276

You should consider what happens when your difference includes 0 days or months. There are plenty possibilites which you must cover:

function getDifference(string $start, string $end): string
{
    $formatted = (new DateTime($end))->diff(new DateTime($start))->format('%y years, %m months, %d days');
    $nonZeros = preg_replace('/(?<!\d)0\s?[a-z]*,\s?/i', '', $formatted);

    $commaPosition = strrpos($nonZeros, ',');

    return $commaPosition ? substr_replace($nonZeros, ' and', $commaPosition, 1) : $nonZeros;
}

var_dump(
    getDifference('2017-12-05', '2018-02-09'),
    getDifference('2017-12-05', '2017-12-09'),
    getDifference('2013-12-05', '2017-12-09'),
    getDifference('2013-12-05', '2017-10-09')
);

The result would be

string(19) "2 months and 4 days"
string(6) "4 days"
string(18) "4 years and 4 days"
string(29) "3 years, 10 months and 4 days"

Upvotes: 0

ishegg
ishegg

Reputation: 9937

A more generic solution. It will store separately each type of diff (year, month, day), and only display it if it's different than 0.

<?php
$fecha1 = \Carbon\Carbon::parse('2017-12-05');
$fecha2 = \Carbon\Carbon::parse('2018-02-09');
$diff = $fecha2->diff($fecha1);
$diffByType = [
    "years" => $diff->format("%y"),
    "months" => $diff->format("%m"),
    "days" => $diff->format("%d"),
];
$output = [];
foreach ($diffByType as $type => $diff) {
    if ($diff != 0) {
        $output[] = $diff." ".$type;
    }
}
echo implode(", ", $output);

Demo

Sample outputs:

For 2017-12-05 and 2018-12-09: 1 years, 4 days

For 2017-12-05 and 2018-02-05: 2 months

Upvotes: 0

Alexey Mezenin
Alexey Mezenin

Reputation: 163788

Use diffInYears():

$format = $fecha2->diffInYears($fecha1) > 0 ? '%y years, %m months and %d days' : '%m months and %d days';
$resta = $fecha2->diff($fecha1)->format($format);

Upvotes: 5

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