CODEWITHSUNDEEP
xmlspringlistspring-iocdefault-implementation
Sagar Sarwe
Sagar Sarwe

Reputation: 3

Override default implementation of list or other collections in spring xml configuration file

I observed that the default implementation of list in spring xml is ArrayList.

I tried:

<bean id="employee" class="com.ioc.entity.Employee">
</property>
        <property name="list">
        <list value-type="java.lang.String">
        <value>ABC</value>
        <value>XYZ</value>
        </list>
        </property>
</bean>

getClass() method on this list returns java.util.ArrayList.

Is there any property or way by which we can override this default implementation of list (may be to LinkedList or any list that I want) or any other collection (like map, set etc.)?

Upvotes: 0

Views: 598

Answers (1)

Dan Conn
Dan Conn

Reputation: 59

You can import Spring util and use the list-class reference.

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
 xmlns:util="http://www.springframework.org/schema/util"
 xsi:schemaLocation="http://www.springframework.org/schema/beans
                     http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
                     http://www.springframework.org/schema/util
                     http://www.springframework.org/schema/util/spring-util-2.5.xsd">

<bean id="employee" class="com.ioc.entity.Employee">
  <property name="list">
    <util:list id="myLinkedList" value-type="java.lang.String" list-class="java.util.LinkedList">
      <value>ABC</value>
      <value>XYZ</value>
    </util:list>
  </property>
</bean>

Upvotes: 0

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