CODEWITHSUNDEEP
pythondictionaryhashsum
nedblorf
nedblorf

Reputation: 5365

How to sum all the values in a dictionary?

Let's say I have a dictionary in which the keys map to integers like:

d = {'key1': 1,'key2': 14,'key3': 47}

Is there a syntactically minimalistic way to return the sum of the values in d—i.e. 62 in this case?

Upvotes: 382

Views: 614376

Answers (11)

Behlul Valiyev
Behlul Valiyev

Reputation: 111

sum(d.values())

  • "d" -> Your dictionary Variable

Upvotes: 9

nemo
nemo

Reputation: 12728

simplest/silliest solution:

https://trinket.io/python/a8a1f25353

d = {'key1': 1,'key2': 14,'key3': 47}
s = 0
for k in d:
    s += d[k]

print(s)

or if you want it fancier:

https://trinket.io/python/5fcd379536

import functools

d = {'key1': 1,'key2': 14,'key3': 47}
s = functools.reduce(lambda acc,k: acc+d[k], d, 0)

print(s)

Upvotes: 1

Tamil Selvan S
Tamil Selvan S

Reputation: 698

USE sum() TO SUM THE VALUES IN A DICTIONARY.

Call dict.values() to return the values of a dictionary dict. Use sum(values) to return the sum of the values from the previous step.

d = {'key1':1,'key2':14,'key3':47}
values = d.values()
#Return values of a dictionary    
total = sum(values)
print(total)

Upvotes: 5

user12988654
user12988654

Reputation: 11

You can get a generator of all the values in the dictionary, then cast it to a list and use the sum() function to get the sum of all the values.

Example:

c={"a":123,"b":4,"d":4,"c":-1001,"x":2002,"y":1001}

sum(list(c.values()))

Upvotes: -1

Rahul Patel
Rahul Patel

Reputation: 94

You could consider 'for loop' for this:

  d = {'data': 100, 'data2': 200, 'data3': 500}
  total = 0
  for i in d.values():
        total += i

total = 800

Upvotes: 0

Reza
Reza

Reputation: 157

phihag's answer (and similar ones) won't work in python3.

For python 3:

d = {'key1': 1,'key2': 14,'key3': 47}
sum(list(d.values()))

Update! There are complains that it doesn't work! I just attach a screenshot from my terminal. Could be some mismatch in versions etc.

enter image description here

Upvotes: 3

phihag
phihag

Reputation: 288260

As you'd expect:

sum(d.values())

Upvotes: 749

Pratyush Raizada
Pratyush Raizada

Reputation: 173

I feel sum(d.values()) is the most efficient way to get the sum.

You can also try the reduce function to calculate the sum along with a lambda expression:

reduce(lambda x,y:x+y,d.values())

Upvotes: 5

Kalyan Pendyala
Kalyan Pendyala

Reputation: 111

d = {'key1': 1,'key2': 14,'key3': 47}
sum1 = sum(d[item] for item in d)
print(sum1)

you can do it using the for loop

Upvotes: 10

martineau
martineau

Reputation: 123541

In Python 2 you can avoid making a temporary copy of all the values by using the itervalues() dictionary method, which returns an iterator of the dictionary's keys:

sum(d.itervalues())

In Python 3 you can just use d.values() because that method was changed to do that (and itervalues() was removed since it was no longer needed).

To make it easier to write version independent code which always iterates over the values of the dictionary's keys, a utility function can be helpful:

import sys

def itervalues(d):
    return iter(getattr(d, ('itervalues', 'values')[sys.version_info[0]>2])())

sum(itervalues(d))

This is essentially what Benjamin Peterson's six module does.

Upvotes: 73

vz0
vz0

Reputation: 32923

Sure there is. Here is a way to sum the values of a dictionary.

>>> d = {'key1':1,'key2':14,'key3':47}
>>> sum(d.values())
62

Upvotes: 21

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