Reputation: 47
I just have a data frame and want to split the data frame by rows, assign the several new data frames to new variables and save them as csv files.
a <- rep(1:5,each=3)
b <-rep(1:3,each=5)
c <- data.frame(a,b)
# a b
1 1 1
2 1 1
3 1 1
4 2 1
5 2 1
6 2 2
7 3 2
8 3 2
9 3 2
10 4 2
11 4 3
12 4 3
13 5 3
14 5 3
15 5 3
I want to split c by column a. i.e all rows are 1 in column a are split from c and assign it to A and save A as A.csv. The same to B.csv with all 2 in column a. What I can do is
A<-c[c$a%in%1,]
write.csv (A, "A.csv")
B<-c[c$a%in%2,]
write.csv (B, "B.csv")
...
If I have 1000 rows and there will be lots of subsets, I just wonder if there is a simple way to do this by using for loop?
Upvotes: 3
Views: 3279
Reputation: 6768
The split()
function is very useful to split data frame. Also, you can use lapply()
here - it should be more efficient than a loop.
dfs <- split(c, c$a) # list of dfs
# use numbers as file names
lapply(names(dfs),
function(x){write.csv(dfs[[x]], paste0(x,".csv"),
row.names = FALSE)})
# or use letters (max 26!) as file names
names(dfs) <- LETTERS[1:length(dfs)]
lapply(names(dfs),
function(x){write.csv(dfs[[x]],
file = paste0(x,".csv"),
row.names = FALSE)})
Upvotes: 3
Reputation: 2431
for(i in seq_along(unique(c$a))){
write.csv(c[c$a == i,], paste0(LETTERS[i], ".csv"))}
You should consider, however, what happens if you have more than 26 subsets. What will those files be named?
Upvotes: 1