CODEWITHSUNDEEP
c++arrayspointersheap-memory
Morchul
Morchul

Reputation: 2037

Create an array of function pointer in heap

I have an array of 6 function pointers:

int (*arrayOfFunPointers[6])();


What I want to do now, is to allocate that array in heap
Because I create the array in a function and return a pointer to that array:

int (*(*fun2())[6])(){

    int (*funPointer)();
    int (*arrayOfFunPointers[6])();
    int (*(*pointerToArrayOfFunPointers)[6])();

    funPointer = &fun;
    arrayOfFunPointers[0] = funPointer;
    pointerToArrayOfFunPointers = &arrayOfFunPointers;

    return pointerToArrayOfFunPointers;
}

Outside of the method, the arrayOfFunPointers lose his validity area and the returned pointer point to "nothing"

I tried a lot like:

int (*arrayOfFunPointers[6])() = new int (*[6])();

or with typedef:

typedef int (*arrayOfFunPointers[6])();
arrayOfFunPointerss *array = new arrayOfFunPointers;

or by assignment to the returned pointer:

pointerToArrayOfFunPointers = new arrayOfFunPointers;
pointerToArrayOfFunPointers = new arrayOfFunPointers[]; //or

But nothing works.

Maybe I do not understand the use of the keyword new correctly, then it would be very helpful if anyone could tell me where I make a thinking mistake

Can anyone help me please? That would be nice

Upvotes: 0

Views: 287

Answers (1)

YSC
YSC

Reputation: 40080

You can simplify your life with tools from C++11. What about:

std::array<FunPointer, 6> getFunctions()
{
    std::array<FunPointer, 6> result;
    // ...
    return result;
}

isn't it just nice? Ne need to bother with dynamic memory, just copy those 6 pointers around, it is relatively cheap.

Upvotes: 3

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