CODEWITHSUNDEEP
pythonpyqtpyqt5qlineeditqpushbutton
barciewicz
barciewicz

Reputation: 3783

Print LineEdit text on a button press

How do I alter the following code to make it print whatever is written in line edit widget when 'OK' button is pressed? The current version returns "'Example' object has no attribute 'textbox'" error.

import sys
from PyQt5.QtWidgets import QApplication, QWidget,QPushButton,QLineEdit, QHBoxLayout, QLabel, QVBoxLayout
from PyQt5.QtGui import QIcon


class Example(QWidget):

    def __init__(self):
        super().__init__()

        self.initUI()


    def initUI(self):

        label = QLabel('Keyword') 
        button = QPushButton('OK')
        textbox = QLineEdit()
        hbox = QHBoxLayout()
        hbox.addWidget(label)
        hbox.addWidget(textbox)
        hbox.addWidget(button)

        vbox = QVBoxLayout()
        vbox.addLayout(hbox)
        vbox.addStretch(1)

        button.clicked.connect(self.button_clicked)

        self.setLayout(vbox)   

        self.setGeometry(300, 300, 300, 220)
        self.setWindowTitle('Icon')
        self.setWindowIcon(QIcon('web.png')) 
        self.show()

    def button_clicked(self):
        print(self.textbox.text())

if __name__ == '__main__':

    app = QApplication(sys.argv)
    ex = Example()
    sys.exit(app.exec_())

`

Upvotes: 1

Views: 2936

Answers (1)

eyllanesc
eyllanesc

Reputation: 243955

if you want that a variable can be accessed in all parts of the class as in your case is the button_clicked method you must make it a member of the class for it you must use self when you create it.

class Example(QWidget):
    [...]

    def initUI(self):    
        label = QLabel('Keyword') 
        button = QPushButton('OK')
        self.textbox = QLineEdit() # change this line
        hbox = QHBoxLayout()
        hbox.addWidget(label)
        hbox.addWidget(self.textbox) # change this line

Upvotes: 1

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