Reputation: 8816
A person can retire when their accumulated corpus is more than required corpus. Hence, for the example shown above, the retirement age will be 55 (i.e., value of E1).
I am having trouble finding the correct formula to locate the column where value in row 2 becomes less than that of row 3.
I tried =MATCH(B2:G2, B3:G3, 1)
for the "less than" match but no luck. Please help.
Upvotes: 1
Views: 67
Reputation: 12113
Try this:
=INDEX($B$1:$G$1,SUMPRODUCT(MATCH(TRUE,B3:G3>B2:G2,0)))
it returns the following, as required:
What's happening here? This line (below) is an array formula which creates an array like {FALSE,FALSE,FALSE,TRUE,TRUE,TRUE}
=B3:G3>B2:G2
However, MATCH
doesn't know how to evaluate the array unless you enter it as an array formula which would usually require entering the formula using Ctrl+Shift+Enter rather than just Enter. A nice trick to avoid having to do this is to wrap the array in a SUMPRODUCT
formula, so that's the only reason for the SUMPRODUCT
. The INDEX
works as normal.
Upvotes: 3
Reputation: 34180
You could also use Aggregate to find the smallest age for which row 3 is greater than row 2
=AGGREGATE(15,6,B1:G1/(B3:G3>B2:G2),1)
Upvotes: 4