CODEWITHSUNDEEP
linuxbashdate
busybee
busybee

Reputation: 53

adding dynamic number of days to a particular date in script

I have a date for example: 20160808 which is stored in a variable $d_date. I have another variable that contains the number of days I need to add to the d_date. Which is $days. Lets say $days=378. I want to add 378 days to $d_date in my script. But it seems to ignore the $days when I use the following command.

end=`date -d "$d_date +$days days" +%Y%m%d`

When I debug the script it shows the following (related to this command):

++ date -d '20160808 + days' +%Y%m%d
+ end=572160721

Upvotes: 3

Views: 689

Answers (1)

Pierre François
Pierre François

Reputation: 6061

This works:

d_date=20160808
days=378
end=`date -d "$d_date +$days days" +%Y%m%d`
echo $end

It gives next output:

20170821

Upvotes: 1

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