CODEWITHSUNDEEP
javascriptregex
Jaypizzle
Jaypizzle

Reputation: 527

Javascript Regex: Mask last 50% of string

Lets say I have a string

var unmasked = 'AwesomeFatGorilla'

What I want to do is mask 50%+ of the string from the end.

var masked = unmasked.replace( //REGEX//, '•')

After replacing, the masked string should look like the following:

AwesomeF•••••••••

Since there were 17 letters in my unmasked string, the last 9 letters were masked. Are there any Regex that works with this?

Upvotes: 4

Views: 296

Answers (2)

Srdjan M.
Srdjan M.

Reputation: 3405

Using Regex .(?!.{n}):

var unmasked = 'AwesomeFatGorilla'
var num = Math.ceil(unmasked.length / 2)
console.log(unmasked.replace(new RegExp(".(?!.{" + num + "})", "g"), "•"))

Upvotes: 1

Gerardo Furtado
Gerardo Furtado

Reputation: 102198

Here is a simple alternative, without Regex:

var unmasked = 'AwesomeFatGorilla'
var masked = unmasked.slice(0, Math.floor(unmasked.length) / 2) + "•".repeat(Math.ceil(unmasked.length / 2));
console.log(masked)

You have to adjust the math for odd lengths Thanks to Rhyono comment below, I'm using Math.floor() and Math.ceil() to get the behaviour you want for odd lengths.

Upvotes: 3

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