CODEWITHSUNDEEP
linuxbash
John
John

Reputation: 855

Get size of image in bash

I want to get size of image. The image is in folder by name encodedImage.jpc 

a="$(ls -s encodedImage.jpc | cut -d " " -f 1)"
temp="$(( $a*1024 * 8))"
echo "$a"

The output is not correct. How to get size? Thank You

Upvotes: 1

Views: 1991

Answers (3)

user8848899
user8848899

Reputation: 311

U can use this command 

du -sh your_file

Upvotes: 0

Gilles Quénot
Gilles Quénot

Reputation: 185025

Better than parsing ls output, the proper way is to use the command stat like this :

stat -c '%s' file

Check 

man stat | less +/'total size, in bytes'

Upvotes: 3

Cheruvian
Cheruvian

Reputation: 5867

If by size you mean bytes or pretty bytes can you just use

ls -lh

 -h      When used with the -l option, use unit suffixes: Byte, Kilobyte, Megabyte, Gigabyte, Terabyte and Petabyte in order to reduce the number of digits to three or less using base 2 for sizes.

I guess the more complete answer if you're just trying to tear off the file size alone (I added the file name as well you can remove ,$9 to drop it)

ls -lh | awk '{print $5,$9}'

Upvotes: 1

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