CODEWITHSUNDEEP
cwindowsfopen
user3747488
user3747488

Reputation: 73

Unable to access file from share drive using fopen in C (windows)

I am taking share drive path as input and adding extra '\' and assigning to a variable.If I use this variable for opening file with "fopen" error is thrown as "No such file or directory".

But If I give the same path (with extra '\' in the path) in the code itself I am able to access.

command: program \\xyz\abc.txt (program_name )

1) My code which doesn't work is like this:

In the program I am making the passed in input path as "\\\\xyz\\abc.txt" by adding extra "\".

then, fopen(var_name,"r"); /* Not working*/

2) Code which works fine:

char arr[100] = "\\\\xyz\\abc.txt"

fopen(arr,"r"); /* works fine */

It seems if the path is known at compile time itself it is working but not at run time.Please suggest what can I do to access path from input not hard coded in program.

Upvotes: 0

Views: 360

Answers (1)

Archie Yalakki
Archie Yalakki

Reputation: 552

You need to escape the backslash in filepath during compile time.. i.e. "\xyz\abc.txt" but runtime has only one slash.

Piece of code to read input from user:

char filename[50]; FILE *fp;

printf("Enter the filename \n"); gets(filename);

fp = fopen(filename, "r");

Upvotes: 2

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