Reputation: 49
I am trying to simulate data 10000 observations for the following distribution:
{ 3x(1-x)2 0 < x < 1
f(x) = { 3(2-x)(1-x)2 1 ≤ x < 2
{ 0 otherwise
Using the rejection method, I am boxing the distribution by the following rectangle: x=0,x=2,y=0,y=2
However, there is some fault in my code below as it doesn't seem to work. Can any one please advise on a fix?
n=10000
t=0
x=0
while(t<n)
{u=runif(1,0,2)
y=runif(1,0,2)
if {(u in c(0:1))
fun=3*u*(1-u)^2
else (u in c(1:2))
fun=3*(2-u)*(1-u)^2}
if (y<fun)
{t=t+1
x[t]=u}}
Upvotes: 0
Views: 75
Reputation: 206167
You have a bunch of R syntax errors. You should review a basic R introduction. be careful with placement of braces. Also there is no in
keyword in R.
n <- 10000
t <- 0
x <- 0
while(t<n) {
u <- runif(1,0,2)
y <- runif(1,0,2)
if (u > 0 & u < 1) {
fun <- 3*u*(1-u)^2
} else if (u >= 1 & u < 2) {
fun <- 3*(2-u)*(1-u)^2
} else {
fun <- 0
}
if (y<fun){
t <- t+1
x[t] <- u
}
}
Upvotes: 1