CODEWITHSUNDEEP
android-filestorage-access-frameworkandroid-storage
Hong
Hong

Reputation: 18501

Is there a straightforward way to get the parent directory's Uri from a file Uri?

Suppose a Uri can be either of the following:

It refers to a file under a directory in both situations.

Is there a straightforward way to get its parent directory's Uri without trying each of the two to see which one works?

[Edit]: Here is an example for SAF:

Uri:

content://com.android.externalstorage.documents/tree/0000-0000%3Atest/document/0000-0000%3Atest%2Ffoo%2FMovies%2FRR%20parking%20lot%20a%202018_02_22_075101.mp4

getPath():

/tree/0000-0000:test/document/0000-0000:test/foo/Movies/RR parking lot a 2018_02_22_075101.mp4

getPathSegments():

0 = "tree"
1 = "0000-0000:test" 
2 = "document"
3 = "0000-0000:test/foo/Movies/RR parking lot a 2018_02_22_075101.mp4"

The parent folder should be test/foo/Movies.

Here is an example for a regular file:

Uri:

file:///storage/emulated/0/foo/Movies/RR%20parking%20lot%20a%202018_02_22_081351.mp4

getPath():

/storage/emulated/0/foo/Movies/RR parking lot a 2018_02_22_081351.mp4

getPathSegments():

0 = "storage"
1 = "emulated"
2 = "0"
3 = "foo"
4 = "Movies"
5 = "RR parking lot a 2018_02_22_081351.mp4"

Upvotes: 6

Views: 2061

Answers (1)

yasirkula
yasirkula

Reputation: 711

3 years late, I had a similar problem. I've resolved it using the Android 26 API DocumentsContract.findDocumentPath. It's OK for me since I use File API on earlier Android versions in my project.

Essentially, I find the document's path using findDocumentPath and remove the last segment from it (i.e. find the parent directory's path). Then, to reform the SAF Uri, I find the last / or : character in the Uri and replace the next part with parent directory's path.

public static String GetParentDirectory( ContentResolver resolver, String rawUri )
{
    if( !rawUri.contains( "://" ) )
    {
        // This is a raw filepath, not a SAF path
        return new File( rawUri ).getParent();
    }
    
    // Calculate the URI's path using findDocumentPath, omit the last path segment from it and then replace the rawUri's path component entirely
    DocumentsContract.Path rawUriPath = DocumentsContract.findDocumentPath( resolver, Uri.parse( rawUri ) );
    if( rawUriPath != null )
    {
        List<String> pathSegments = rawUriPath.getPath();
        if( pathSegments != null && pathSegments.size() > 0 )
        {
            String rawUriParentPath;
            if( pathSegments.size() > 1 )
                rawUriParentPath = Uri.encode( pathSegments.get( pathSegments.size() - 2 ) );
            else
            {
                String fullPath = pathSegments.get( 0 );
                int separatorIndex = Math.max( fullPath.lastIndexOf( '/' ), fullPath.lastIndexOf( ':' ) + 1 );
                rawUriParentPath = separatorIndex > 0 ? Uri.encode( fullPath.substring( 0, separatorIndex ) ) : null;
            }

            if( rawUriParentPath != null && rawUriParentPath.length() > 0 )
            {
                int rawUriLastPathSegmentIndex = rawUri.lastIndexOf( '/' ) + 1;
                if( rawUriLastPathSegmentIndex > 0 )
                {
                    String rawUriParent = rawUri.substring( 0, rawUriLastPathSegmentIndex ) + rawUriParentPath;
                    if( !rawUriParent.equals( rawUri ) )
                        return rawUriParent;
                }
            }
        }
    }

    return null;
}

Upvotes: 2

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