CODEWITHSUNDEEP
mongodbpython-2.7pymongo
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Reputation: 8961

failed to catch duplicate error

from pymongo.errors import DuplicateKeyError

def insert_duplicate_token(self):
        try:                       
            fields = ..
            token = Token.create_a_new_document(fields)
            token.save()
            token = Token.create_a_new_document(fields)
            token.save()

            self.logger.info('success')

        except DuplicateKeyError:
            self.logger.exception('Duplicate caught')

        except Exception, err:
            self.logger.exception('failed...')
            return False

The error raised is u'Tried to save duplicate unique keys (E11000 duplicate key error collection: oauth_test.tokens index: idx_access_token dup key: { : "gRULKp6sqPWRYDrJNrvaifMhlaC8qvzfZOpqTZLTPxHnQ691vT" })'

but is caught in Exception, and not in DuplicateKeyError

tried 

import pymongo
pymongo.errors - does not exists

here is the stacktrace

Traceback (most recent call last):
  File "move_invalid_tokens_worker.py", line 91, in insert_duplicate_token
    token.save()
  File "/Users/ohadperry/.virtualenvs/oauth/lib/python2.7/site-packages/mongoengine/document.py", line 386, in save
    raise NotUniqueError(message % unicode(err))
NotUniqueError: Tried to save duplicate unique keys (E11000 duplicate key error collection: oauth_test.tokens index: access_token_1 dup key: { : "MIeJey0f3rWkedMZacDIjDMB3a04ilrbdieKaZ2BWt0lI0sATP" })

weird..

Upvotes: 1

Views: 1713

Answers (1)

WebQube
WebQube

Reputation: 8961

I answered myself with the stackstrace, thanks @Arount

from pymongo.errors import DuplicateKeyError
from mongoengine import NotUniqueError 

def insert_duplicate_token(self):
        try:                       
            fields = ..
            token = Token.create_a_new_document(fields)
            token.save()
            token = Token.create_a_new_document(fields)
            token.save()

            self.logger.info('success')

        except (NotUniqueError, DuplicateKeyError), error:
            self.logger.exception('Duplicate caught')

        except Exception, error:
            self.logger.exception('failed...')
            return False

Upvotes: 3

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