Ajith k James
Ajith k James

Reputation: 148

Common JSON Format for Django Rest Framework responses for Android client

I am developing the rest apis for an android app using Djnago Rest Framework. The android guys told me that it would be nice if I could provide the responses in a common format, like

{
   “Status”:””,
   “Message”:””,
   “Data”:[]
}

Guys, is it the right approach? If so, how to achieve this? My assumption is that using a middleware would be an option.

Thanks in advance.

Upvotes: 5

Views: 2809

Answers (5)

Jitendra Meena
Jitendra Meena

Reputation: 21

Common JSON Format

Success Response for Retrieving a List of Books

    {
  "status": "success",
  "message": "Books retrieved successfully.",
  "data": [
    {
      "id": 1,
      "title": "1984",
      "author": "George Orwell",
      "published_year": 1949
    },
    {
      "id": 2,
      "title": "To Kill a Mockingbird",
      "author": "Harper Lee",
      "published_year": 1960
    }
  ]
}

Error Response for Validation Error

    {
  "status": "error",
  "message": "Validation error occurred.",
  "errors": {
    "title": [
      "This field is required."
    ],
    "published_year": [
      "Ensure this field has at least 4 characters."
    ]
  }
}

Thanks in advance.

Upvotes: 0

Olushola Albert
Olushola Albert

Reputation: 1

Tweaking @Muhammad Hassan answer, i was able to do this

For custom 200 response

def custom200(message, data):
    return Response(
        {
            "status": "Success",
            "status_code": 200,
            "message": message,
            "data": data,
        },
        status=status.HTTP_200_OK,
    )

For custom 400 response

def custom400(message):
    return Response(
        {
            "status": "Failed",
            "status_code": 400,
            "message": message,
        },
        status=status.HTTP_400_BAD_REQUEST,
    )

And use in your viewset like this

return custom200(message="Success Message", data=my_data)
return custom400(message="Error Message ")

Upvotes: 0

Atul Mishra
Atul Mishra

Reputation: 2018

Writing your own reponse function will not help, in case you are using class based views say APIView or generic views. I think a better way could be to write custom renderer for formatting successfull responses and custom exception handler for responses with errors. This implementation gives you a single point to control all reponses without changing your already existing views. Here is the sample code from one of my project. You need modify it as per your requirements.

Custom Renderer

#renderers.py
class CustomJSONRenderer(JSONRenderer):

def render(self, data, accepted_media_type=None, renderer_context=None):

    response_data = {'message': '', 'errors': [], 'data': data, 'status': 'success'}

    getattr(renderer_context.get('view').get_serializer().Meta,'resource_name', 'objects')

    # call super to render the response
    response = super(CustomJSONRenderer, self).render(response_data, accepted_media_type, renderer_context)

    return response

Custom Exception Handler

# custom_exception_handler.py
def custom_exception_handler(exc, context):
  # Call REST framework's default exception handler first,
  # to get the standard error response.
  response = exception_handler(exc, context)

  # Now add the HTTP status code to the response.
  if response is not None:

    errors = []
    message = response.data.get('detail')
    if not message:
        for field, value in response.data.items():
            errors.append("{} : {}".format(field, " ".join(value)))
        response.data = {'data': [], 'message': 'Validation Error', 'errors': errors, 'status': 'failure'}
    else:
        response.data = {'data': [], 'message': message, 'error': [message], 'success': 'failure'}

  return response

Override REST_FRAMEWORK settings to use these renderer and exception handler.

REST_FRAMEWORK = {
  # Add custom renderer.
  'DEFAULT_RENDERER_CLASSES'=(
              'path.to.CustomJSONRenderer',
              'rest_framework.renderers.JSONRenderer',
              'rest_framework.renderers.BrowsableAPIRenderer'),
  # Add cutom exception handler
  'EXCEPTION_HANDLER': 'path.to.custom_exception_handler'
   }

Upvotes: 11

Muhammad Hassan
Muhammad Hassan

Reputation: 14391

You can write function for customized django rest response and reuse it. Below is the way you can do this.

def custom_response(status_code=status.HTTP_200_OK, message='', data):
    return Response(
        {
             "status": status_code, 
             "message": message, 
              "data": data
        },
        status=status.HTTP_200_OK
    )

In this way response code for request will always be 200 but you can provide what ever code you want in status_code value. You can use this like this.

return custom_response(status_code=status.HTTP_200_OK, message='Data saved successfully', data=my_serialized_data)

Upvotes: 2

Mehul Kabaria
Mehul Kabaria

Reputation: 6622

Yes its Right way to implement common response.

For that you have to create one Generic class which one is common used while handle API response just you have to pass Different List as your API response.

Your Generic class should be like below.

public class Status<T> {
    @SerializedName("Message")
    @Expose
    private String message;
    @SerializedName("Status")
    @Expose
    private String status;
    @SerializedName("Data")
    @Expose
    private T result;

    public String getMessage() {
        return message;
    }

    public void setMessage(String message) {
        this.message = message;
    }

    public String getStatus() {
        return status;
    }

    public void setStatus(String status) {
        this.status = status;
    }

    public T getResult() {
        return result;
    }

    public void setResult(T result) {
        this.result = result;
    }
}

Upvotes: -2

Related Questions