CODEWITHSUNDEEP
listsortinggroovy
supersighs
supersighs

Reputation: 947

Sort a list of lists in Groovy

Sorry if this is a straight forward thing, I'm new to Groovy. I'm trying to figure out how to sort this list on the "uses" key in each sub list, but I can't seem to get it figured out:

[[name:foo, uses:2], [name:bar, uses:1], [name:baz, uses:4]]

I'm hoping to get the following result:

[[name:baz, uses:4], [name:foo, uses:2], [name:bar, uses:1]]

Does someone out there know how to best handle this? I checked similar questions but couldn't find anything pertaining to Groovy.

Thanks in advance.

Upvotes: 0

Views: 3293

Answers (3)

jpertino
jpertino

Reputation: 2219

just wanted to add a shorter version

[[name:'foo', uses:2], [name:'bar', uses:1], [name:'baz', uses:4]].sort{-it.uses}​​​​​

Upvotes: 3

Jeff Storey
Jeff Storey

Reputation: 57192

The easiest way to do it would be to use the sort method

def sorted = lists.sort( {a, b -> b["uses"] <=> a["uses"] } )
sorted.each { 
 println it
}

// prints
// [name:baz, uses:4]
// [name:foo, uses:2]
// [name:bar, uses:1]

Upvotes: 5

supersighs
supersighs

Reputation: 947

I think I figured it out...

sort{a,b -> b['uses'] <=> a['uses']}

...seems to do the trick.

Upvotes: 3

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