Reputation: 23
I have the following code to merge two sorted linked lists:
struct node* merge(struct node* a, struct node* b)
{
struct node dummy;
struct node* tail = &dummy;
dummy.next = NULL;
while(1)
{
if(a == NULL)
{
tail->next = b;
break;
}
else if (b == NULL)
{
tail->next = a;
break;
}
if (a->data <= b->data)
{
MoveNode(&(tail->next), &a);
}
else
{
MoveNode(&(tail->next), &b);
}
tail = tail->next;
}
return(dummy.next);
}
void MoveNode(struct node** destRef, struct node** sourceRef)
{
struct node* newNode = *sourceRef;
*sourceRef = newNode->next;
newNode->next = *destRef;
*destRef = newNode;
}
And it worked fine. I was trying to make it into a recursive method and this is what I got:
struct node* Merge(struct node* a, struct node* b)
{
struct node* result;
if (a == NULL)
return(b);
else if (b==NULL)
return(a);
if (a->data <= b->data)
{
result = Merge(a->next, b);
}
else
{
result = Merge(a, b->next);
}
return(result);
}
But it has many of the nodes missing in the result. What is wrong?
Upvotes: 2
Views: 582
Reputation: 454970
Your base conditions are correct. But there is problem with your recursive condition.
When you compare a
's data with b
's data you are not copying node a
or node b
into result
.
Try:
struct node* result;
if (a == NULL)
return(b);
else if (b==NULL)
return(a);
if (a->data <= b->data)
{
// make result point to node a.
result = a;
// recursively merge the remaining nodes in list a & entire list b
// and append the resultant list to result.
result->next = Merge(a->next, b);
}
else
{
result = b;
result->next = Merge(a, b->next);
}
return(result);
Upvotes: 3