CODEWITHSUNDEEP
rfor-loopcut
user9092800
user9092800

Reputation:

create interval with for loop

we can use cut to create interval data further to be label, also by utilize for loop

enter image description here

cut function

perform_vec <- perform[["Performance"]]
perf_labs <- c(1,2,3,4,5,6)
perfcut <- cut(perform_vec,breaks = c(0,25,49.99,69.99,84.99,94.99,101),right = F, labels = perf_labs)
perfcut_df <- as.data.frame(cbind(perform_vec, perfcut))
perfcut_df$perfcut <- factor(perfcut_df$perfcut, levels = c(1,2,3,4,5,6), labels = c("D","C","B-","B","A-","A"))

resulting in the following:

enter image description here

i want to create it with for loop

Upvotes: 0

Views: 1080

Answers (1)

G. Grothendieck
G. Grothendieck

Reputation: 269461

In solution #1 we count, in a loop, how many breaks each input value exceeds and then use that to index into labels. Solution #2 does the same but using outer rather than a loop. Solution #3 uses cut.

# input
x <- c(30, 50, 80)
breaks <- c(0,25,49.99,69.99,84.99,94.99,101)
labels <- c("D","C","B-","B","A-","A")

# solutions

# 1 - loop
lev <- 0 * x
for (b in breaks) lev <- lev + (x > b)
factor(labels[lev], levels = labels)
## [1] C  B- B 
## Levels: D C B- B A- A

# 2 - outer
factor(labels[rowSums(outer(x, breaks, `>`))], levels = labels)
## [1] C  B- B 
## Levels: D C B- B A- A

# 3 - cut
cut(x, breaks, labels)
## [1] C  B- B 
## Levels: D C B- B A- A

Upvotes: 2

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