CODEWITHSUNDEEP
javascript
H. Bada
H. Bada

Reputation: 29

trouble with if condition

i call this function like this: calculate(2)

function calculate(flag)
{
   if (flag==1)
   {
   }
   else if (flag==2)
   {  
   }
   else (flag==3)
   {  
   }
}

In the debugger i see, that it jumps also to else (flag==3) (apart from else if (flag==2)). Could someone explain it to me?

thanks H.Bada

Upvotes: -1

Views: 115

Answers (4)

Foram
Foram

Reputation: 1

As else doesn't check any condition so from your example (flag==3) is considered as the statement enclosed in your else block i.e. the first statement after else & everything else after that statement is out of the if... else block.

So every statement thereafter will be executed regardless of the value of your variable flag.

Upvotes: 0

rlb.usa
rlb.usa

Reputation: 15043

Several things are going on, and you're being confused by a syntax error:

 else (flag==3)

else doesn't take a boolean condition like if and else if do.

See @El Ronnoco's post for the correct syntax.

Upvotes: 0

Maxpm
Maxpm

Reputation: 25571

Your code is being interpreted like this:

if (flag == 1)
{
}
else if (flag == 2)
{
}
else
{
    (flag == 3)
}

You probably want another else if statement:

else if (flag == 2)
{
}
else if (flag == 3)
{
}

Upvotes: 1

El Ronnoco
El Ronnoco

Reputation: 11922

Please post your code using the {} code button so that it shows up nicely!

You don't want the final else (flag==3) you either want else if (flag==3) or just else

eg

function calculate(flag)
{
   if (flag==1)
   {
   }
   else if (flag==2)
   {  
   }
   else if (flag==3)
   {  
      //this will execute if flag is 3
   }
}

or

function calculate(flag)
{
   if (flag==1)
   {
   }
   else if (flag==2)
   {  
   }
   else
   {  
        //this will execute if flag is not 1 or 2
   }
}

Upvotes: 6

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