CODEWITHSUNDEEP
ruby
David West
David West

Reputation: 2328

Ruby - is there a shorthand check for two logical conditionals against one variable

How can I shorten this expression?

if artist != 'Beck' && artist != 'Led Zeppelin'
  5.times { puts 'sorry' }
end

Is there a shorthand check for two logical conditionals against one variable?

As an aside, this turned into

class String
  def is_not?(*arr)
    !arr.include?(self)
  end
end

In our project.

Now we can do 'foo'.is_not?('bar', 'batz')

Upvotes: 0

Views: 55

Answers (3)

sawa
sawa

Reputation: 168101

case artist
when 'Beck', 'Led Zeppelin'
else
  5.times { puts 'sorry' }
end

Upvotes: 0

pjs
pjs

Reputation: 19855

Your specific case is pretty minimal, but if you have lots of unrelated conditions to test for lots of values you can set the tests up as lambdas in an array and use all?. For instance, the following example filters all the integers between 1 and 100 for those which are > 20, < 50, even, and divisible by 3:

tests = [
  ->(x) { x > 20 },
  ->(x) { x < 50 },
  ->(x) { x.even? },
  ->(x) { x % 3 == 0 }
]

(1..100).each do |i|
  puts i if tests.all? { |test| test[i] }
end

Upvotes: 1

Sergio Tulentsev
Sergio Tulentsev

Reputation: 230346

unless ['Beck', 'Led Zeppelin'].include?(artist)
  5.times { puts 'sorry' }
end

Isn't any "shorter", but no obscure syntax trickery too. Just using regular array api. As a consequence, you can provide that array in any way you want. Load it from a file, for example. With any number of elements.

Upvotes: 3

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