Simplify bitwise operation

Question

I've a if statement like this:

if ((x & y) == y && (x & z) == 0) { /* do something... */}

Is possible to simplify this if statement removing the && operator and using only bitwise operators?

Answer 1

A short equivalent expression is

(x & (y ^ z)) == y

which is probably easiest to see correct by looking at all 8 results for a single bit (this is sufficient since the result for each bit is independent of all other bits).