Reputation: 81
I found this syntax to copy and paste from one workbook specific sheet to another workbook. however, what i need help with is how to paste the copied information to a specific cell in the second workbook/sheet. like i need to information to be pasted in cell B3 instead of A1. Thank you
import openpyxl as xl
path1 = "C:/Users/almur_000/Desktop/disandpopbyage.xlsx"
path2 = "C:/Users/almur_000/Desktop/disandpopbyage2.xlsx"
wb1 = xl.load_workbook(filename=path1)
ws1 = wb1.worksheets[0]
wb2 = xl.load_workbook(filename=path2)
ws2 = wb2.create_sheet(ws1.title)
for row in ws1:
for cell in row:
ws2[cell.coordinate].value = cell.value
wb2.save(path2)
wb2 is path2 "C:/Users/almur_000/Desktop/disandpopbyage2.xlsx"
Upvotes: 4
Views: 43537
Reputation: 799
To copy paste the entire sheet from work book to another.
import pandas as pd
#change NameOfTheSheet with the sheet name that includes the data
data = pd.read_excel(path1, sheet_name="NameOfTheSheet")
#save it to the 'NewSheet' in destfile
data.to_excel(path2, sheet_name='NewSheet')
Upvotes: 0
Reputation: 81
thank you for those helping me. I found the answer with slight modification. I have removed the last def statement and kept every thing else as it is. it works fantastically. copy and paste in the place i need without removing anything from the template.
`#! Python 3
import openpyxl
#Prepare the spreadsheets to copy from and paste too.
#File to be copied
wb = openpyxl.load_workbook("foo.xlsx") #Add file name
sheet = wb.get_sheet_by_name("foo") #Add Sheet name
#File to be pasted into
template = openpyxl.load_workbook("foo2.xlsx") #Add file name
temp_sheet = template.get_sheet_by_name("foo2") #Add Sheet name
#Copy range of cells as a nested list
#Takes: start cell, end cell, and sheet you want to copy from.
def copyRange(startCol, startRow, endCol, endRow, sheet):
rangeSelected = []
#Loops through selected Rows
for i in range(startRow,endRow + 1,1):
#Appends the row to a RowSelected list
rowSelected = []
for j in range(startCol,endCol+1,1):
rowSelected.append(sheet.cell(row = i, column = j).value)
#Adds the RowSelected List and nests inside the rangeSelected
rangeSelected.append(rowSelected)
return rangeSelected
#Paste range
#Paste data from copyRange into template sheet
def pasteRange(startCol, startRow, endCol, endRow, sheetReceiving,copiedData):
countRow = 0
for i in range(startRow,endRow+1,1):
countCol = 0
for j in range(startCol,endCol+1,1):
sheetReceiving.cell(row = i, column = j).value = copiedData[countRow][countCol]
countCol += 1
countRow += 1
def createData():
print("Processing...")
selectedRange = copyRange(1,2,4,14,sheet) #Change the 4 number values
pastingRange = pasteRange(1,3,4,15,temp_sheet,selectedRange) #Change the 4 number values
#You can save the template as another file to create a new file here too.s
template.save("foo.xlsx")
print("Range copied and pasted!")`
Upvotes: 2
Reputation: 3823
Since the OP is using the openpyxl
module I wanted to show a way to do this using that module. With this answer I demonstrate a way to move the original data to new column and row coordinates (there may be better ways to do this).
This fully reproducible example first creates a workbook for demonstration purposes called 'test.xlsx', with three sheets named 'test_1', 'test_2' and 'test_3'. Then using openpyxl
, it copies 'test_2' into a new workbook called 'new.xlsx' shifting the cells over 4 columns and down 3 columns. It makes use of the ord()
and chr()
functions.
import pandas as pd
import numpy as np
import openpyxl
# This section is sample code that creates a worbook in the current directory with 3 worksheets
df = pd.DataFrame(np.random.randn(10, 3), columns=list('ABC'))
writer = pd.ExcelWriter('test.xlsx', engine='xlsxwriter')
df.to_excel(writer, sheet_name='test_1', index=False)
df.to_excel(writer, sheet_name='test_2', index=False)
df.to_excel(writer, sheet_name='test_3', index=False)
wb = writer.book
ws = writer.sheets['test_2']
writer.close()
# End of sample code that creates a worbook in the current directory with 3 worksheets
wb = openpyxl.load_workbook('test.xlsx')
ws_name_wanted = "test_2"
list_all_ws = wb.get_sheet_names()
for item in list_all_ws:
if item != ws_name_wanted:
remove = wb.get_sheet_by_name(item)
wb.remove_sheet(remove)
ws = wb['%s' % (ws_name_wanted)]
for row in ws.iter_rows():
for cell in row:
cell_value = cell.value
new_col_loc = (chr(int(ord(cell.coordinate[0:1])) + 4))
new_row_loc = cell.coordinate[1:]
ws['%s%d' % (new_col_loc ,int(new_row_loc) + 3)] = cell_value
ws['%s' % (cell.coordinate)] = ' '
wb.save("new.xlsx")
Here's what 'test.xlsx' looks like:
And here's what 'new.xlsx' looks like:
Upvotes: 3