Reputation: 610
I have a dataframe sample looks like below. first row is header.
a b c d e
x 1 10 4 asd
y 3 12 5 aqe
z 4 14 6 rty
t 6 12 4 abd
v 7 4 8 yul
I would like the find a column members by filtering d column by its minimum value. I tried the sort it and select the 0. element but column may have 2 minimum values like in the sample.
Output should be "x" and "t"
Any suggestions?
Upvotes: 1
Views: 82
Reputation: 862661
Use boolean indexing
with loc
for select column a
and last convert to list
:
L = df.loc[df['d'] == df['d'].min(), 'a'].tolist()
print (L)
['x', 't']
Detail:
print (df['d'] == df['d'].min())
0 True
1 False
2 False
3 True
4 False
Name: d, dtype: bool
Upvotes: 2