Reputation: 378
and I want to display all the data of the clients who have the 'Campagne' A. So here is what I want :
Any idea ?
Thanks.
Upvotes: 1
Views: 1189
Reputation: 31
The inner calculate is a filter where the client participated in Champagne A. Using the filter, the outer calculate displays the table with the correct clients.
EVALUATE
CALCULATETABLE (
Campaigne,
CALCULATETABLE (
DISTINCT ( Campaigne[Client] ),
Campaigne[Campagne] = "A" )
)
Upvotes: 0
Reputation: 40264
You can create the second table as a calculated table using the following:
TableA = FILTER(Table1,
"A" IN CALCULATETABLE(
VALUES(Table1[Campagne]),
ALL(Table1),
Table1[Client] = EARLIER(Table1[Client])))
If you want a True / False
calculated column on your original table, you can just use the conditional part of the above:
ClientA = "A" IN CALCULATETABLE(
VALUES(Table2[Campagne]),
ALL(Table2),
Table2[Client] = EARLIER(Table2[Client]))
What these are doing is taking the whole table (ALL
line), filtering it to look at the Client
in the current row (EARLIER
line), and finding all the distinct Campagne
associated with that Client
any row (VALUES
line) of this filtered table. Once we have those values, we check if "A" is a member.
Upvotes: 2
Reputation: 854
You could use the code from the figure below, however you should add an extra column for this.
Upvotes: 0