CODEWITHSUNDEEP
c++anonymous-types
eonil
eonil

Reputation: 86155

How to access anonymous union/struct member in C++?

This question is my mistake. The code described below is being built well with no problem.

I have this class.

Vector.h

struct  Vector
{
    union
    {
        float   elements[4];
        struct
        {
            float   x;
            float   y;
            float   z;
            float   w;
        };                  
    };

    float   length();
}

Vector.cpp

float Vector::length()
{
  return x;  // error: 'x' was not declared in this scope
}

How to access the member x,y,z,w?

Upvotes: 4

Views: 6067

Answers (2)

Karl von Moor
Karl von Moor

Reputation: 8614

You need an instance of your struct inside the anonymous union. I don't know exactly what you want to achive, but e.g. something like this would work:

struct Vector
{
  union
  {
    float elements[4];
    struct
    {
      float x, y, z, w;
    }aMember;
  };

  float length() const
  {
    return aMember.x;
  }
};

Upvotes: 5

Fiktik
Fiktik

Reputation: 1941

What you have created is not an anonymous member, but anonymous type (which is useless by itself). You have to create a member of your anonymous type. This concerns both your struct and your union.

Adjust the header like this:

struct  Vector
{
    union
    {
        float   elements[4];
        struct
        {
            float   x;
            float   y;
            float   z;
            float   w;
        } v;
    } u;

    float   length();
};

Now you can access your members like this:

u.elements[0] = 0.5f;
if(u.v.x == 0.5f) // this will pass
    doStuff();

Upvotes: 4

Related Questions