CODEWITHSUNDEEP
c#
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Reputation: 982

Converting a hex value to byte with 8 digits in C#

I receive a value of "7". Using my code below. I get "111" but what I need is "0000111" and if I receive "255" I get "1001010101" but what I need to get is "11111111". Please see my code below:

_dataRx = ((SerialPort) (sender)).ReadLine();
_dataRx = _dataRx.Replace("\r\n", "").Replace("\r", "").Replace("\n", "");
var x = Convert.ToString(Convert.ToInt32(_dataRx, 16), 2);
Console.WriteLine(x);

I need to have 8 digits always since I need to place it in an array. Can you please help. Thank you.

Upvotes: 1

Views: 820

Answers (1)

Dmitrii Bychenko
Dmitrii Bychenko

Reputation: 186668

Actually you want to treat _dataRx (say, "255") as a decimal, not hexadecimal value (0x255 == 597 == 1001010101 (binary) when 255 == 0xFF = 11111111 (binary) required):

string x = Convert.ToString(int.Parse(_dataRx), 2).PadLeft(8, '0');

Upvotes: 6

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