CODEWITHSUNDEEP
java
2345678
2345678

Reputation: 69

Finding the shortest word in a string array

I am trying to find the shortest word from a string array, but I am removing special characters using reg ex with the code

public String[] setWordArray(String stringToBeAnaylsedForFrequency) {
        stringToBeAnaylsedForFrequency = stringToBeAnaylsedForFrequency.replaceAll("\\d+", " ");
        stringToBeAnaylsedForFrequency = stringToBeAnaylsedForFrequency.replaceAll("\\W", " ");
        stringToBeAnaylsedForFrequency = stringToBeAnaylsedForFrequency.replaceAll("( )+ ", " ");
        String[] wordArray = stringToBeAnaylsedForFrequency.split(" ");
        return wordArray;
}

and this is the method for use 

public String getShortestWordInStringGiven() {
        int wordArrayLength = getStringArrayForGivenString().length;
        String shortestWordInGivenString = getStringArrayForGivenString()[0];
        for (int i = 1; i < wordArrayLength ; i++) {
            if (getStringArrayForGivenString()[i].length() < shortestWordInGivenString.length()) {
                shortestWordInGivenString = getStringArrayForGivenString()[i];
            }
        }
        return shortestWordInGivenString;
    }

when it works fine i input text like hello you, it would return you as the shortest character, but when i input "hello you" with a special character at the start it returns nothing.

Upvotes: 0

Views: 442

Answers (1)

Olaf Kock
Olaf Kock

Reputation: 48057

Answering to your comments: When you have a space in the beginning, split will have one more element, an empty String, in the beginning. That one is the shortest element in the array (check for the array's length), but printing it reveals nothing that's visible. But, rest assured, the correct element is printed: it's ""

You might want to trim your String before the split operation

Upvotes: 2

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