Reputation: 10204
How can I use a linux command to get the wall time in seconds spent for executing a program. In the example below,I expected to get "0.005".
$ time ls >/dev/null
real 0m0.005s
user 0m0.001s
sys 0m0.003s
Upvotes: 2
Views: 894
Reputation: 36229
Depending on your path:
/usr/bin/time -f "%e"
The normal time is given by bash's (if you happen to use bash) intern time command
type time
while you need the one,
which time
will find.
So in context of your command:
/usr/bin/time -f "%e" ls > /dev/null
But to store it in a variable, you can't use
a=$(/usr/bin/time -f "%e" ls > /dev/null)
because the output of time is written to the error stream, to not inflict with the programs output (in this example ls
). See the manpage of time
for further details.
An alternative to call a program, which is by default replaced by a bash builtin like time or echo, is, to precede it with the keyword command
:
command time -f "%e" ls
Upvotes: 4