CODEWITHSUNDEEP
bashshellsyntax
Omar Amaoun
Omar Amaoun

Reputation: 526

Error while using (( ... )) in Bash if condition

#!/bin/bash
A='';B='';C='';D=''
function returnFunctionWebService()
{
        touch test.json
        curl http://localhost:9099/BelattarProject/StudentMail.php -o test.json
        for line in `cat test.txt`;do
                echo $line
                A=$(echo $line | cut -d ',' -f1)
                echo $A
                B=$(echo $line | cut -d ',' -f2)
                echo $B
                C=$(echo $line | cut -d ',' -f3)
                echo $C
                D=$(echo $line | cut -d ',' -f4)
                echo $D
        done
}
returnFunctionWebService
echo $A $B $C $D
if [ -n $A ]; then
        if(( "$A" = "\"test1\"" )); then
                echo -e "c'est juste"
                exit
        else
                echo -e "c'est pas juste"
                exit
        fi
fi

i have an error at this end which is ./scriptWeb.sh: line 22: ((: "test1" = "test1" : syntax error: operand expected (error token is ""test1" = "test1" ") some help please

Upvotes: 3

Views: 82

Answers (1)

codeforester
codeforester

Reputation: 43039

(( )) can only be used for integer arithmetic, not for string comparisons. For strings, use [[ ]] construct, this way:

if [[ "$A" = "\"test1\"" ]]; then

There are many issues in your script. Get it checked at shellcheck

See also:

Upvotes: 4

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