CODEWITHSUNDEEP
iosobjective-cjson
Jhovarie Guiang
Jhovarie Guiang

Reputation: 37

Cannot get single result from JSON

I am trying to parse a simple JSON using Objective-C. My JSON file looks like the following:

{ "videosource": "hello my value" }

And my iOS Objective-C code:

NSError *error;
NSString *url_string = [NSString stringWithFormat: @"http://www.mywebsite.com/test"];
NSData *data = [NSData dataWithContentsOfURL: [NSURL URLWithString:url_string]];
NSMutableArray *json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
NSLog(@"my -> json: %@", json);

//NSString *str = json[0]; //<- this one doest not work it makes app crush
//__NSSingleEntryDictionaryI objectAtIndexedSubscript:]: unrecognized selector sent to instance

//NSUInteger num = 0;
//NSString *str = [json objectAtIndex:num]; <- this one doest not work it makes app crush

I am trying to get the value from videosource key of JSON. How to do it?

Upvotes: 0

Views: 71

Answers (1)

rmaddy
rmaddy

Reputation: 318774

Your JSON is a dictionary, not an array. { } means dictionary. [ ] means array. Pretty straightforward.

NSError *error = nil;
NSString *url_string = @"http://www.mywebsite.com/test";
NSData *data = [NSData dataWithContentsOfURL: [NSURL URLWithString:url_string]];
NSDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
if (json) {
    NSString *source = json[@"videosource"];
} else {
    NSLog(@"Error parsing JSON: %@", error);
}

Also, you really should not be using NSData dataWithContentsOfURL:. Use NSURLSession to get data from a remote URL.

Upvotes: 2

Related Questions