Reputation: 42
I've made a function that reads a file and separates the first line from the rest.
The two files which I'm using for this are aaa.txt
and bbb.txt
. I try to manipulate the data. I tried squaring each element of each string but I realize that I need to float it but I'm not sure why it won't just float. Where did I went wrong?
aaa.txt
is below
test a line 1
3,6,8,99,-4,0.6,8
0,9,7,5,7,9,5
2,2,2,2,2,2,5
7,5,1,2,12,8,0.9
=====================
bbb.txt
is as below
test b line 1
1,2,3,4,5,6,7,8
55,0,90,09,1,2,3,
8,9,7,6,8,7,6
3,43,5,8,2,4,1
======================
def mi_func(P):
f=open(P, 'r')
first = f.readline()
restlines= f.readlines()
f.close()
return first, restlines
afirst,arest = mi_func('aaa.txt')
bfirst,brest = mi_func('bbb.txt')
print(arest)
print(brest)
##################
#convert a rest into a float here
#convert b rest into a float here
#################
for i in range(len(arest)):
arest[i] = [float(x) for x in arest[i].strip().split(',')]
for i in range(len(brest)):
brest[i] = [float(x) for x in brest[i].strip().split(',')]
p=[i**2 for i in arest] #square each element of a rest
c=[i**2 for i in brest] #square each element of b rest
print(p)
print(c)
['3,6,8,99,-4,0.6,8\n', '0,9,7,5,7,9,5\n', '2,2,2,2,2,2,5\n', '7,5,1,2,12,8,0.9\n']
['1,2,3,4,5,6,7,8\n', '55,0,90,09,1,2,3,\n', '8,9,7,6,8,7,6\n', '3,43,5,8,2,4,1']
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
<ipython-input-1-36603657d444> in <module>()
21
22 for i in range(len(brest)):
---> 23 brest[i] = [float(x) for x in brest[i].strip().split(',')]
24
25
<ipython-input-1-36603657d444> in <listcomp>(.0)
21
22 for i in range(len(brest)):
---> 23 brest[i] = [float(x) for x in brest[i].strip().split(',')]
24
25
ValueError: could not convert string to float:
Upvotes: 0
Views: 505
Reputation: 6255
I found your mistake, it seems that you have some new line characters and some empty characters and a '09' (in brest) that you are trying to cast to a float
So you need to remove them first. With your code it was just a couple simple tweaks:
def mi_func(P):
f=open(P, 'r')
first = f.readline()
restlines= f.readlines()
f.close()
return first, restlines
afirst,arest = mi_func('aaa.txt')
bfirst,brest = mi_func('bbb.txt')
#This code will remove leading 0's and split numbers into a list
#while eliminating any standalone new line characters:
arest = [x.lstrip('0').split(',') for x in arest if x != '\n']
brest = [x.lstrip('0').split(',') for x in brest if x != '\n']
for i in range(len(arest)):
arest[i] = [float(x)**2 for x in arest[i] if x != '\n' and x!= '']
print(arest, 'a')
for i in range(len(brest)):
brest[i] = [float(x)**2 for x in brest[i] if x != '\n' and x != '']
print(brest, 'b')
# This is your output
#[[81.0, 49.0, 25.0, 49.0, 81.0, 25.0], [4.0, 4.0, 4.0, 4.0, 4.0, 4.0, 25.0]] a
#[[3025.0, 0.0, 8100.0, 81.0, 1.0, 4.0, 9.0], [64.0, 81.0, 49.0, 36.0, 64.0, 49.0, 36.0]] b
Upvotes: 1
Reputation: 11520
You can use this function to return firstline, float list from the text files you provided.
def mi_func(file_name):
with open(file_name) as f:
lines = f.readlines()
float_list = [
float(float_str)
for line in lines[1:]
for float_str in line.strip().split(',')
if float_str != None
]
return lines[0].strip(), float_list
print(mi_func('aaa.txt'))
print(mi_func('bbb.txt'))
Upvotes: 0