CODEWITHSUNDEEP
phpbash
Keverw
Keverw

Reputation: 3786

convert Bash command to php

This is the bash command echo -n x && (echo 618cf954-6576-491d-8ac6-a1b888c4705d |xxd -r -p |openssl base64|tr '/+' '_-')

This is my php

<?
$uuid = "618cf954-6576-491d-8ac6-a1b888c4705d";
$voiceid = "x" . $uuid;
$voiceid  = base64_encode($voiceid);
$voiceid = str_replace("+", "-", $voiceid);
$voiceid = str_replace("/", "_", $voiceid);
echo $voiceid;
?>

The bash gives the right output, the php one isn't. I'm not sure what i need to do deferent in php.

The output should be xYYz5VGV2SR2KxqG4iMRwXQ==

A C++ version is at https://gist.github.com/1e096b658097c19cf309

Upvotes: 1

Views: 856

Answers (2)

Dennis Williamson
Dennis Williamson

Reputation: 359855

Also, in the Bash version, the "x" isn't included in the pipe through xxd and openssl. If you want it to be then do this:

{ echo -n x; echo -n 618cf954-6576-491d-8ac6-a1b888c4705d; } | xxd -r -p | openssl base64 | tr '/+' '_-')

If, on the other hand, you want the PHP to match the existing Bash:

<?
$uuid = "618cf954-6576-491d-8ac6-a1b888c4
$voiceid = str_replace("-", "", $uuid);
$voiceid = pack("H*", $voiceid);
$voiceid  = base64_encode($voiceid);
$voiceid = str_replace("+", "-", $voiceid);
$voiceid = str_replace("/", "_", $voiceid);
$voiceid = "x" . $voiceid;
echo $voiceid;
?>

You will need to use pack to convert the hex string to binary.

Edit: Fixed several of my errors.

Upvotes: 3

Jander
Jander

Reputation: 5627

I think the following line is wrong:

$voiceid = "x" . $uuid;

Adding the "x" onto the string should be the last thing you do before the PHP echo.

Upvotes: 3

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