CODEWITHSUNDEEP
regex
Fierce82
Fierce82

Reputation: 408

Regex to catch strings with only 2 digits

I have searched for similar questions, and even though I found several answers, none seams to work. I have a list of strings

Z189
I142
M395
L210
V467
M203
Q277
Q461
Y440
S250
M162
Q96
22Q
W148
Q72
T22T
22TWE22
12E34

and I need a regex to find only strings holding only 2 digits (not more or less). So in this case:

Q96, 22Q, Q72, T22T

my failed attempts include:

\D\d{2}\D
(?<!\d)\d{2}(?!\d)

Upvotes: 2

Views: 3994

Answers (4)

Zenoo
Zenoo

Reputation: 12880

You could use ^\D*(\d)\D*(\d)\D*$

\D* makes sure anything before your first digit isn't another digit.

(\d) captures your first digit.

\D* makes sure there is no other digits between your two digits.

(\d) captures your second digit.

\D* makes sure anything after your second digit isn't another digit.

Upvotes: 6

David
David

Reputation: 6111

You didn't mention if the digits had to be sequential, but all of your examples had them as such. The following RegEx will only match lines that contain exactly two sequential digits:

^\D*\d{2}\D*$

Explained:

  • ^ matches the beginning of the String
  • \D* matches any non-digit zero or more times
  • \d{2} matches exactly two digits
  • \D* matches any non-digit zero or more times
  • $ matches the end of the String

Fiddle: Live Demo

Upvotes: 2

user7125259
user7125259

Reputation:

This works well. Note the global and multiline flags.

/^[a-zA-z]\d{2}[a-zA-Z]*$/gm

Explanation: Start of line -> letter -> exactly two digits -> zero or more letters -> end of line

Upvotes: 2

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626853

To match a string that only contains 2 digits at any location, you may use

^\D*(?:\d\D*){2}$

See the regex demo

Details

  • ^ - start of string
  • \D* - any 0+ chars other than digits
  • (?:\d\D*){2} - 2 repetitions of:
    • \d - a digit
    • \D* - any 0+ chars other than digits
  • $ - end of string.

Upvotes: 2

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