CODEWITHSUNDEEP
iosarraysiphoneswiftmath
user9469498
user9469498

Reputation:

Swift 2d array minimum

I have an 2d array like this:

let array= [ [0,2], [4,5], [4,1], [0,4] ]

and I'd like to get ONE element thats 0. index is the smallest in the array.

Result should be this:

let result = [0,2] // not also [0,4] because just the first one

This is what I've tried so far but obviously this is not a working solution :p

let result = array.filter { $0[1].map { return $0.min() } }

Thanks in advance, jonas

Upvotes: 0

Views: 320

Answers (1)

David Pasztor
David Pasztor

Reputation: 54745

You can simply use Array.min then compare the first element of the nested arrays. min will return the first element in the original array that fits the minimum function in the closure in case there were several minima.

let array = [ [0,2], [4,5], [4,1], [0,4] ]
let result = array.min(by: {$0.first! < $1.first!}) //[0,2]

Upvotes: 1

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