CODEWITHSUNDEEP
reactjs
Ruham
Ruham

Reputation: 759

React: state-based rendering

I have the following React component:

class Parent extends Component {
  constructor(props) {
    super(props)
    this.state = {
      isRendered: false
    }
  }

  render() {
    return (
      <div className="result">
        Rendering result
      </div>
    )
  }
}

Based on the state of this.state.isRendered, I want my <div> component to render if the state is true, and not render if the state is false.

What would be the best way to organize it in React?

Upvotes: 1

Views: 197

Answers (5)

Jun Bach
Jun Bach

Reputation: 111

You can use simple conditional ternary operator to do this: 

condition ? if_true_result : if_false_result

Your code should be like this:

render() {
    const {isRendered} = this.state;
    return isRendered ?
       <div className="result">
         Rendering result
       </div>
     : ''
  }

Another official way is following the guidelines about Conditional Rendering in Reactjs document: https://reactjs.org/docs/conditional-rendering.html

Upvotes: 1

Kevin Qian
Kevin Qian

Reputation: 2720

Just check this.state.isRendered in the render. Here I used a simple AND check. Click on the button to change state and see how it works (snippet takes a short while to run):

class Parent extends React.Component {
  constructor(props) {
    super(props)
    this.state = {
      isRendered: false
    }
  }

  render() {
    const {
      isRendered
    } = this.state;

    return (
      <div>
      {isRendered &&
        <div className="result">
          Rendering result
        </div>
      }
      <button onClick={() => {this.setState({isRendered: !isRendered})}}>{isRendered? 'Hide' : 'Show'}</button>
      </div>
    )
  }
}

ReactDOM.render(<Parent />, document.getElementById('app'))
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>
<div id="app"></div>

Upvotes: 3

Liam
Liam

Reputation: 6743

There are many ways to accomplish that

{ this.state.isRendered ? 
<div className="result">
        This if the isRendered is true
      </div>
: <div className="result">
        This if the isRendered is false
      </div> }

Upvotes: 0

Dom
Dom

Reputation: 1816

You are allowed to return null or false for React components. So, if you don't want anything to get rendered, you could do the following:

  ...

  render() {
    if (!this.state.isRendered) return null

    return (
      <div className="result">
        Rendering result
      </div>
    )
  }

or, alternatively

  ...

  render() {
    return this.state.isRendered && (
      <div className="result">
        Rendering result
      </div>
    )
  }

Upvotes: 1

Pixelomo
Pixelomo

Reputation: 6737

Using a ternary operator check whether isRendered is true else return null:

class Parent extends Component {
  constructor(props) {
    super(props)
    this.state = {
      isRendered: false
    }
  }

  render() {
    return (
      <div>
      {this.state.isRendered ?
        <div className="result">
          Rendering result
        </div> : null
      }
      </div>
    )
  }
}

Upvotes: 1

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