CODEWITHSUNDEEP
javascriptboolean
Manish
Manish

Reputation: 131

Mathematical Operator over Boolean values in JavaScript

Can someone explain what will be the order of execution of following JavaScript Code:

(true + false) > 2 + true

I understand using + operator over two Boolean values returns the result as 0,1 or 2 depending upon the values being provided.

I interpreted output of above code as 1 by breaking the execution in following order:

1) (true + false) // Outputs : 1
2) 1 > 2 // Outputs : false
3) false + true //Outputs : 1

But the actual result is:

false

Can anyone correct my understanding if am interpreting the code in wrong way.

Upvotes: 2

Views: 44

Answers (2)

Nina Scholz
Nina Scholz

Reputation: 386883

What you have is a question of operator precedence, of three parts,

  • ( ... ) grouping with the highest precedence of 20,

  • + adition with precedence of 13, and

  • > greater than (here) with the lowest precendece of 11.

That means the operators with higer precedence are evaluated first and the comes the once with lower precedence.

(true + false) > 2 + true
(true + false)             -> 1
                 2 + true  -> 3

             1 > 3         -> false

Upvotes: 1

Suren Srapyan
Suren Srapyan

Reputation: 68685

Your 2nd point is not correct.

1) (true + false) outputs - 1
2) (2 + true) - outputs 3
3) 1 > 3 - outputs false

You can check this using functions

(true + false) > 2 + true

function f1() {
  const cond = true + false;
  console.log(cond);
  return cond;
}

function f2() {
  const cond = 2 + true;
  console.log(cond);
  return cond;
}

console.log(f1() > f2());

If you want to compare with 2 then add true, you must to wrap into the parentheses

((true + false) > 2) + true

Upvotes: 2

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