CODEWITHSUNDEEP
pythonmatrixsympymodulus
ANTZY21
ANTZY21

Reputation: 87

Sympy Matrix M (modulo n)... How?

import sympy

I am trying to find a matrix after taking each of its values (mod n). I know numpy arrays work fine with this but i have to use sympy unfortunately. Does anyone know of an inbuilt sympy function that does this or any other way round it? Thank you!

B = sympy.Matrix([[2, 3], [4, 5]])
print(B % 3)

This is my error

TypeError: unsupported operand type(s) for %: 'MutableDenseMatrix' and 'int'

with numpy this is the correct output:

B = np.array([[2, 3], [4, 5]])
print(B % 3)

>>> [[2 0]
    [1 2]]

Upvotes: 2

Views: 1457

Answers (2)

smichr
smichr

Reputation: 19135

With current SymPy this works:

>>> import sympy
>>> B = sympy.Matrix([[2, 3], [4, 5]])
>>> print(B % 3)
Matrix([[2, 0], [1, 2]])

Upvotes: 0

drilow
drilow

Reputation: 412

You can use applyfunc to apply a function to every element: B.applyfunc(lambda x : x % 3)

Upvotes: 1

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