CODEWITHSUNDEEP
djangopython-3.x
AlxVallejo
AlxVallejo

Reputation: 3219

python Django command argument parsing returning an array

I have this simple Django command I'm writing as such:

def add_arguments(self, parser):
    parser.add_argument('--type', nargs='+', type=str)
    parser.add_argument('--overwrite', nargs='?', type=bool, default=False)
    parser.add_argument('--unsubscribe', nargs='?',
                        type=bool, default=False)

def handle(self, *args, **options):

    print(options['type'])

If I run myCommand --type=all I see my type printed as ['all']. Why is this coming back as an array? I just want the string value all.

Upvotes: 1

Views: 476

Answers (1)

krs
krs

Reputation: 4154

Its because your nargs, where you tell it to give you a list.

Read more here https://docs.python.org/3/library/argparse.html#nargs

where we can see that

'+'. Just like '*', all command-line args present are gathered into a list. Additionally, an error message will be generated if there wasn’t at least one command-line argument present.

So you probably want '?' which parses a single value.

Upvotes: 4

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