CODEWITHSUNDEEP
phpmysqlarrays
GeneCode
GeneCode

Reputation: 7588

SHOW TABLES not returning correct items in array

I have multiple tables named like so MOM2016, MOM2017, MOM2018.

When i run query in phpmyadmin

SHOW TABLES LIKE 'MOM%'

it returns 3 items as expected.

BUT!!!! When i run in php, my code seem to give me only 1 item in the array (first one only MOM2016).

$sql = "SHOW TABLES LIKE 'MOM%'";
$result = $conn->query($sql);
$dbArray = $result->fetch_assoc();
echo "DEBUG:".count($dbArray);

This give:

DEBUG:1

My php code is wrong? Pls help.

Upvotes: 0

Views: 87

Answers (2)

Nick
Nick

Reputation: 147286

If you want to get all the results at once,

$dbArray = $result->fetch_all();
echo "DEBUG:".count($dbArray);

Upvotes: 1

Napoli
Napoli

Reputation: 1403

Iterate through your fetch resource

$dbArray = array();
while ($row = $result->fetch_assoc()) {
   $dbArray[] = $row;
}

print "DEBUG: " . count($dbArray);

Upvotes: 1

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