CODEWITHSUNDEEP
htmlcsscss-selectors
Ketan
Ketan

Reputation: 619

Hide first 4 div after every 10th div element

I want to hide after every 10 div element first 4 div element. So how it's possible using nth-of-type OR any other style css.

Any one have idea for my question then please update me.

Upvotes: 0

Views: 76

Answers (1)

Bhuwan
Bhuwan

Reputation: 16855

Try to use nth-child css selector here...you want 4 elements after every 10th element so use 10n+11, 10n+12, 10n+13, 10n+14...

Note: I have changed the color of selected element just for visual...use display:none to hide...

.parent {
  display: flex;
  flex-wrap: wrap;
}

.parent div:nth-child(10n+11),
.parent div:nth-child(10n+12),
.parent div:nth-child(10n+13),
.parent div:nth-child(10n+14) {
  background: red;
  color: #fff;
}

.parent div {
  padding: 10px;
  background: #ccc;
  font: 13px Verdana;
  font-weight: bold;
  margin: 4px;
  color: #000;
}
<div class="parent">
  <div>1</div>
  <div>2</div>
  <div>3</div>
  <div>4</div>
  <div>5</div>
  <div>6</div>
  <div>7</div>
  <div>8</div>
  <div>9</div>
  <div>10</div>
  <div>11</div>
  <div>12</div>
  <div>13</div>
  <div>14</div>
  <div>15</div>
  <div>16</div>
  <div>17</div>
  <div>18</div>
  <div>19</div>
  <div>20</div>
  <div>21</div>
  <div>22</div>
  <div>23</div>
  <div>24</div>
  <div>25</div>
  <div>26</div>
</div>

Upvotes: 5

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