CODEWITHSUNDEEP
node.jsmongodbmongoose
dev dev
dev dev

Reputation: 123

find distinct Data

I need to find the all viewed experiences from collections its working but there are duplicate entries i need to use distinct by expId i don't know how to use distinct here. please help i am new here. 

function getViewedExperiences(){
    return new Promise(function(resolve,reject){
        Views.find({userId: req.userId},function(err,result){
            if(err){
                reject(err);
            }else{
                resolve(result);
            }
        });
    });
}

my result is - 

{
"msg": "Recently Viewed Experiences",
"data": [
    {
        "_id": "5aab6ad75ed3dc24ac5c492c",
        "userId": "5aaa662357421667e989a286",
        "expId": "5aab533972beff1c9880eb86",
        "__v": 0,
        "created": "2018-03-16T06:57:27.694Z"
    },
    {
        "_id": "5aab6b475ed3dc24ac5c492d",
        "userId": "5aaa662357421667e989a286",
        "expId": "5aab52e272beff1c9880eb85",
        "__v": 0,
        "created": "2018-03-16T06:59:19.975Z"
    },
    {
        "_id": "5aab6bc75ed3dc24ac5c492e",
        "userId": "5aaa662357421667e989a286",
        "expId": "5aab52e272beff1c9880eb85",
        "__v": 0,
        "created": "2018-03-16T07:01:27.973Z"
    }
  ]
}

here how i use distinct??

Upvotes: 0

Views: 42

Answers (1)

Houssem Romdhani
Houssem Romdhani

Reputation: 332

Try this:

function getViewedExperiences(){
    return new Promise(function(resolve,reject){
        Views.distinct('expId', {userId: req.userId},function(err,result){
            if(err){
                reject(err);
            }else{
                resolve();
            }
        });
    });
}

Upvotes: 1

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