CODEWITHSUNDEEP
bashawk
Uni VPS
Uni VPS

Reputation: 99

Awk/Bash move digits from front of line to end of line

I want to move the digits/numeric string from front of line to end of line, example of input:

123example
321example
34292example

expected output:

example123
example321
example34292

Upvotes: 1

Views: 372

Answers (5)

Rahul Verma
Rahul Verma

Reputation: 3089

GNU awk

awk -F"[[:digit:]]+" '{split($0,f,FS,s); print $2 s[1]}' file
example123
example321
example34292

You can use stream of digits as FS. Split the string using FS and the characters matching the separators will be stored in array s. Use it as you like

Upvotes: 1

Claes Wikner
Claes Wikner

Reputation: 1517

First remove example and put it back in front of what is left.

awk '{sub(/example$/,"");print "example"$0}' file

example123
example321
example34292

Upvotes: 0

Cyrus
Cyrus

Reputation: 88654

With bash and a regex:

s="123example"
[[ $s =~ ([0-9]+)(.*) ]] && echo "${BASH_REMATCH[2]}${BASH_REMATCH[1]}"

Output:

example123

Upvotes: 2

RavinderSingh13
RavinderSingh13

Reputation: 133538

Following awk may help you without using array in match:

awk '{gsub(/\r/,"");match($0,/^[0-9]+/);print substr($0,RSTART+RLENGTH+1) substr($0,RSTART,RLENGTH)}' Input_file

Also added now gsub(/\r/,"") for removing all carriage returns from your Input_file too.

Also in case you want to save output into your Input_file itself then append following to above code > temp_file && mv temp_file Input_file

Explanation: Adding explanation too here now.

awk '
{
  gsub(/\r/,"")                                              ##Removing all carriage returns from current line here by using gsub out of box function of awk.
  match($0,/^[0-9]+/);                                       ##Using match function of awk to match starting digits in current line.
  print substr($0,RSTART+RLENGTH+1) substr($0,RSTART,RLENGTH)##Printing substrings here 1st substring is to print from the value of RSTART+RLENGTH+1 to till the end of the line and second substring is to print from the RSTART to RLENGTH where RSTART and RLENGTH are the variables of awk which will be SET once match is having a TRUE value in it. RSTART denotes the index value of matched regex in line/variable and RLENGTH is the length of the matched regex by match.
}
' Input_file                                                ##Mentioning the Input_file name here.

Upvotes: 1

Flopp
Flopp

Reputation: 1947

GNU awk's match function can do the job:

gawk 'match($0, /^([0-9]+)(.*)$/, m) {print m[2] m[1]}' yourfile.txt

but, honestly, I would use sed for this task (as @anubhava suggested).

Upvotes: 5

Related Questions